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7
Consider the line y=-x-5.
x-s.
Find the equation of the line that is perpendicular to this line and passes through the point (4, 6).
Find the equation of the line that is parallel to this line and passes through the point (4, 6).

Respuesta :

rasuka

Answer:

y = x + 2

Step-by-step explanation:

1.) identify the gradient in the given equation

M1= -1

2.) use the formula to find the next gradient

formula: M1 × M2 = -1

-1 × M2 = -1 ( divide by -1 on both side)

M2 = 1

3.)use the formula

[tex]y - y1 = m(x - x1)[/tex]

y - 6 = 1 ( x- 4)

y - 6 =1x -4(add 6 on both side)

y = x + 2

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