Respuesta :
The speed of an object is its distance traveled per unit time
The average speed required for the remainder of the trip 55.5
The reason the average speed value is correct is given as follows:
The known parameters;
The length of the first part of the trip, L = 218 mile
Duration of the time the sales person travels, t₁ = 2 hours and 15 minute
Average speed of travel, v₁ = 64 mph
The time at which the salesperson arrive at the destination, t₂ = 1 hour and 20 minutes
Required:
To find the average speed required for the remainder of the trip
Solution:
Distance traveled = Speed × Time
The distance traveled on the first part of the trip, d₁ = v₁ × t₁
(t₁ = 2 hours and 15 minute = 2.25 hours)
∴ d = 64 mph × 2.25 hours = 144 miles
The distance of the remainder part of the trip, d₂ = L - d₁
d₂ = 218 mile - 144 mile = 74 mile
The average speed required for the remainder of the trip, v₂, is given as follows;
[tex]v_2 = \dfrac{d_2}{t_2}[/tex]
t₂ = 1 hour and 20 minutes = [tex]1\frac{1}{3} \ hour = \frac{4}{3} \, hour[/tex]
Therefore;
[tex]v_2 = \dfrac{74 \ mile}{1\frac{1}{3} \ hour} = 55.5 \ mph[/tex]
With the units left out, we have;
The average speed required for the remainder of the trip, v₂ = 55.5
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