this is my last question plz help me.

Answer:
Step-by-step explanation:
[tex]f(x)=2x^2 -3x[/tex] [tex]f(-3)[/tex]
[tex]g(x)=-3x-3[/tex] [tex]g(5)[/tex]
Replace everywhere "x" is with the given function. Then solve:
[tex]f(x)=2x^2 -3x\\\\f(x)=2(-3)^2-3(-3)[/tex]
Use PEMDAS
[tex]-3 \times -3 = 9[/tex]
[tex]f(x)=2(-3)^2-3(-3)\\\\f(x)=2(9)-3(-3)[/tex]
[tex]2 \times 9 = 18\\3\times-3=-9\\18- (-9)=27[/tex]
[tex]f(x)=27[/tex]
[tex]g(x)=-3x-3\\\\g(x)=-3(5)-3\\-3\times 5 = -15\\-15-3=-18[/tex]
[tex]g(5) = -18[/tex]
(Please! MAKE sure to ask me how and why I solved every SINGLE equation. I will answer ASAP! Please feel free to do so :)