Using baseball concepts, it is found that:
- The player had 48 at bats.
- The player had 44 total bases.
- The player had a slugging percentage of 91.67%.
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- The slugging percentage is given by the number of bases multiplied by 100% divided by the number of at bats.
- The number of at bats is the sum of home runs, triples, doubles, singles and outs.
[tex]AB = 1 + 4 + 6 + 16 + 21 = 48[/tex]
- Thus, the player had 48 at bats.
- A home run is worth 4 bases, a triple worth 3, double worth 2, single worth 1 and out worth 0, thus, the number of total bases is:
[tex]TB = 4(1) + 3(4) + 6(2) + 16(1) + 21(0) = 44[/tex]
- Thus, the player had 44 total bases.
- The slugging percentage is:
[tex]SLG = \frac{TB \times 100\%}{AB} = \frac{44 \times 100\%}{48} = 91.67\%[/tex]
- The player had a slugging percentage of 91.67%.
A similar problem is given at https://brainly.com/question/13193262
