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A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of the compound?​

Respuesta :

Answer:

So first understand that empirical formula refers to ratio of different atoms in lowest integer form.

To calculate this let's make mol C as our default ratio of 1* and divide everything by 0.528 mol.

Na 1.06/0.528 = 2.00757575758

C 0.528/0.528 = 1

O 1.59/0.528= 3.01136364

Na2CO3

It's sodium carbonate

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