The volume of a box is the amount of space in the box.
The 1.5 cutout would have a greater volume than the 1.75 cutout
From the complete question, the dimension of the paper is:
[tex]\mathbf{Length = 11in}[/tex]
[tex]\mathbf{Width = 8in}[/tex]
Assume that the cutout is x.
The volume of the box would be:
[tex]\mathbf{Volume = (11 - 2x) \times (8 - 2x) \times x}[/tex]
1.75 cutout
Substitute 1.75 for x in the volume equation
[tex]\mathbf{Volume = (11 - 2x) \times (8 - 2x) \times x}[/tex]
[tex]\mathbf{Volume = (11 - 2\times 1.75) \times (8 - 2\times 1.75) \times 1.75}[/tex]
[tex]\mathbf{Volume = 59.0625}[/tex]
1.5 cutout
Substitute 1.5 for x in the volume equation
[tex]\mathbf{Volume = (11 - 2x) \times (8 - 2x) \times x}[/tex]
[tex]\mathbf{Volume = (11 - 2\times 1.5) \times (8 - 2\times 1.5) \times 1.5}[/tex]
[tex]\mathbf{Volume = 60}[/tex]
By comparing the above values of volume, we can conclude that the 1.5 cutout would have a greater volume than the 1.75 cutout
Read more about volumes at:
https://brainly.com/question/15861918
