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What is the net displacement of the particle between 0 seconds and 80 seconds?

A. 160 meters
B. 80 meters
C. 40 meters
D. 20 meters
E. 0 meters​

What is the net displacement of the particle between 0 seconds and 80 secondsA 160 metersB 80 metersC 40 metersD 20 metersE 0 meters class=

Respuesta :

9514 1404 393

Answer:

  E. 0 meters​

Explanation:

The net displacement is the area under the velocity curve, taking signs into account.

Here, the shape of the curve is triangular, so we can use geometry to figure the area. The area of a triangle is given by ...

  A = 1/2bh

For the first 40 seconds, the triangle has a base of (40 s) and a height of (+4 m/s). Then the area is ...

  A = (1/2)(40 s)(4 m/s) = 80 m

For the next 40 seconds, the triangle has a base of (40 s) and a height of (-4 m/s). The area of that triangle is ...

  A = (1/2)(40 s)(-4 m/s) = -80 m

Then the net displacement is 80 m - 80 m = 0 m over the 80 s period.

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Additional comment

You can see right away that the curve is symmetrical about the point (40, 0), so will have a net zero area on the interval [0, 80].