Albert has saved $720, and every month he saves $80 more. John has saved $480, and every month he saves $120 more. Which of these gives the correct inequality and solution that shows for what number of months, n, John will have saved over $160 more than Albert?

Respuesta :

The correct inequality is [tex]40n-240>160:n>10 months[/tex]

It is given that Albert has saved $[tex]720[/tex], and every month he saves $[tex]80[/tex] more. John has saved $[tex]480[/tex], and every month he saves $[tex]120[/tex] more.

We will solve this problem using Arithmetic progression

For Albert:

[tex]a_{m}=720,d=80\\a_{n} =720+80n,n>m[/tex]

For John:

[tex]a_{m} =480,d=120\\a_{n} =480+120n,n>m[/tex]

John saved money=[tex]160[/tex] more than Albert

[tex]480+120n-(720+80n)>160\\-240+40n>160\\40n-240>160:n>10 months[/tex]

Therefore the correct inequality is [tex]40n-240>160:n>10 months[/tex]

Learn  more about Arithmetic progression from here:

https://brainly.in/question/22234492