5) Two knights are jousting on horseback. It takes 2.2 seconds for the knights to meet in the middle
of the course and collide. If one knights horse ran at 6m/s and the other's horse at 9m/s, then
how far apart must they have been begin with?

We know that since they meet in the middle, and dont stop, that both knights take the same time to travel to the middle. This means that if they are traveling at a constant speed we can easily calculate the distance each travels

Step 2: Model it with Equations

General equation: V = D/t [m/s]

T = D1 + D2 = V1*t + V2*t = t * (v1 + v2)

Step 3: Sub in knowns

T = 2.2 s* (6m/s + 9m/s)

T = 33m

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5) Two knights are jousting on horseback. It takes 2.2 seconds for the knights to meet in the middle of the course and collide. If one knights horse ran at 6m/s and the other's horse at 9m/s, then how far apart must they have been begin with?

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5) Two knights are jousting on horseback. It takes 2.2 seconds for the knights to meet in the middle
of the course and collide. If one knights horse ran at 6m/s and the other's horse at 9m/s, then
how far apart must they have been begin with?