Answer:
-8 and -6.
Step-by-step explanation:
Let the first even integer be a.
Since the second is a consecutive even integer, it is given by (a + 2).
Half of the smaller (i.e. a) is equal to two more than the larger (i.e. a + 2). In other words:
[tex]\displaystyle \frac{a}{2} = (a + 2) + 2[/tex]
Solve for a:
[tex]\displaystyle \begin{aligned}\displaystyle \frac{a}{2} &= (a + 2) + 2\\ \\ \frac{a}{2} &= a + 4\\ \\ a &= 2a + 8 \\ \\ a &= -8 \end{aligned}[/tex]
In conclusion, the two even, consecutive integers are -8 and -6.
