Respuesta :
[tex] {ab}^{2} = \sqrt{( {7 - ( - 1))}^{2} +( { - 3 - 3)}^{2} } \\ = \sqrt{ {8}^{2} + { - 6 }^{2} } \\ = \sqrt{64 + 36 } \\ = \sqrt{100 } \\ ab = 10[/tex]
[tex] {bc}^{2} = \sqrt{( {4 - 7)}^{2} + {(1 - ( - 3))}^{2} } \\ = \sqrt{{ - 3}^{2} + {4}^{2} } \\ = \sqrt{ 9 + 16} \\ = \sqrt{25} \\ bc = 5[/tex]