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A triangle has side lengths of (7n-2p)(7n−2p) centimeters, (2n+4q)(2n+4q) centimeters, and (q-5p)(q−5p) centimeters. Which expression represents the perimeter, in centimeters, of the triangle?

Respuesta :

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Answer:

(7n-2p)(7n−2p) + (2n+4q)(2n+4q) + (q-5p)(q−5p) OR

53n² +29p² +17q² -14np +8nq -10pq

Step-by-step explanation:

The perimeter is found by adding all the side lengths.

P = (7n-2p)(7n−2p) + (2n+4q)(2n+4q) + (q-5p)(q−5p)

We know that (a+b)(a+b) = (a+b)², and (a-b)(a-b) = (a-b)²

P = (7n-2p)² + (2n+4q)² +  (q-5p)²

We know that (a+b)² = a²+b²+2ab, and (a-b)² = a²+b²-2ab

P = 49n² + 4p² - 14np +4n² +16q² + 8nq +q²+25p² -10pq

Combine like terms

P = 53n² +29p² +17q² -14np +8nq -10pq