9514 1404 393
Answer:
A √40
Step-by-step explanation:
The given radical expression can be written as ...
[tex]\displaystyle 2\sqrt{n+4}=\sqrt{2^2}\cdot\sqrt{n+4}=\sqrt{4(n+4)}=\sqrt{4n+16}[/tex]
The last two versions of this expression tell you two things:
- the value under the radical must be a multiple of 4
- the value under the radical is greater than 16
Only one answer choice meets these requirements:
√40
