Find the value of x in the isosceles triangle shown below.
74
774
7
2

Answer:
c:10
Step-by-step explanation:
7^2+ [tex]\sqrt{74} ^{2}[/tex] = [tex]x^{2}[/tex]
[tex]x^{2}[/tex] = 25
x =5 (but that is only 1/2 of the length you are looking for
5*2 = 10