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In parallelogram ABCD, m∠B = 105°.

What is the value of x. (Round your answer to the nearest tenth, if necessary.)

will mark brainliest help In parallelogram ABCD mB 105 What is the value of x Round your answer to the nearest tenth if necessary class=

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Answer:

52.5

Step-by-step explanation:

Since ED ≈ AD, ∆AED is a isosceles triangle where <EAD and <AED has same angle measurement

Now, m<B = 105°, since ABCD is a parallelogram, <B = <D

so, m<ADC = 105° so, m<ADE = 180°-105° = 75°

Now, m<EAD+m<AED+m<ADE = 180°

or, m<AED+m<AED+m<ADE = 180°

or, x+x+75°=180°

or, 2x=180+75°

or, 2x=105°

or, x=52.5°

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