Respuesta :

leena

Hi there!

[tex]\large\boxed{log_b3b = 1.8397}[/tex]

Keep in mind the following log property:

logₓab = logₓa + logₓb

Thus:

[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]

We know the value of log_b3, and a log with the same values for the base equals 1. Thus:

[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]