Answer:
the super train is not completely within the tunnel.
Explanation:
From the given information:
The proper length [tex]L_o[/tex] = 1200 ft
The super train speed = 0.99c
By applying the concept of length contraction, the contracted length of the super-train can be determined by using the formula:
[tex]L = L_o \sqrt{1-\dfrac{v^2}{c^2}}[/tex]
[tex]L = 1200 \sqrt{1-\dfrac{(0.99c)^2}{c^2}}[/tex]
[tex]L = 1200 \sqrt{1-(0.99)^2}[/tex]
[tex]L = 1200 \sqrt{1-0.9801}[/tex]
[tex]L = 1200 \sqrt{0.0199}[/tex]
L = 169.3 ft
≅ 169 ft
Thus, the contracted length is 169 ft more than the proper length of the tunnel L' 50 ft.
As such, the super train is not completely within the tunnel.
