A juice machine is set to dispense 16 ounces of juice. The amount of juice
dispensed is normally distributed, with a mean of 16.15 ounces and a
standard deviation of 0.25 ounces. In which range will the amount of juice
dispensed be found 68% of the time?​

A juice machine is set to dispense 16 ounces of juice The amount of juice dispensed is normally distributed with a mean of 1615 ounces and a standard deviation class=

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Answer: A): 15.90 ounces to 16.4 ounces.

Step-by-step explanation:

Considering the standard deviation is 0.25 ounces. The mean of the juice is 16.15 ounces. Additionally, 68% is one standard deviation away from the mean.

With that being said, you would do the following calculations:

[tex]16.15-0.25=15.90\\\\16.15+0.25=16.40[/tex]

This question relates to The Empirical Rule and understanding how it works. A brief summary is that within one standard deviation of the mean, that is where 68% of the data lies. Two standards deviations is 95%. And three standard deviations is 99.5%.

The formula: [tex]u\frac{+}{-} o[/tex]

the mean PLUS OR MINUS the standard deviation.

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Answer:

A

Step-by-step explanation: