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Wires manufactured for use in a computer system are specified to have resistances between 0.14 and 0.16 ohms. The actual measured resistances of the wires produced by company A have a normal probability distribution with mean 0.15 ohm and standard deviation 0.005 ohm. (Round your answers to four decimal places.) (a) What is the probability that a randomly selected wire from company A's production will meet the specifications

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Answer:

Hence the probability that a randomly selected wire from company A's production will meet the specifications is 0.95455.

Step-by-step explanation:

a)[tex]P(0.14 < x < 0.16 ) = P[(0.14 - 0.15)/ 0.005) < (x - \mu) /\sigma < (0.16 - 0.15) / 0.005) ][/tex]

[tex]=P(0.14 < x < 0.16 ) = P[(0.14 - 0.15)/ 0.005)< ((x - 0.15) /0.005) < (0.16 - 0.15) / 0.005) ][/tex]

[tex]=P(z<\frac{0.01}{0.005} )- P(z<-\frac{0.01}{0.005})[/tex]  

Using z table,  

= 0.9773 - 0.02275  

= 0.95455.

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