Answer:
[tex]by \: rotation : \\ { \bf{AB + BC = CD+ AD}} \\ { \boxed{ \tt{AB - CD = BC - DA}}}[/tex]
since: DA = -AD
Answer:
Here are all the answers (this took me awhile to figure out myself)
Step-by-step explanation:
Statement 1: ABCD is a parallelogram.
Reason 1: Given
Statement 2: draw AC.
Reason 2: Unique line postulate.
Statement 3: BCA & DAC are alt. interior angles.
Reason 3: def. of alt. interior angles.
Statement 4: DCA & BAC are alt. interior angles.
Reason 4: def. of alt. interior angles.
Statement 5: AB || CD
Reason 5: def. of parallelogram
Statement 6: BC || DA
Reason 6: def. of parallelogram
Statement 7: <BCA = <DAC
Reason 7: alternative interior angle theorem
Statement 8: <DCA = <BAC
Reason 8: alternative interior angle theorem
Statement 9: AC = AC
Reason 9: reflexive property
Statement 10: ABC = CDA
Reason 10: ASA
Statement 11: AB = CD
Reason 11: CPCTC
Statement 12: BC = DA
Reason 12: CPCTC
