Answer:
Explanation:
Given that:
The mass of aluminium oxide Al₂O₃ = 2000 kg = 2000 000 g
Molar mass of Al₂O₃ = 101.96 g/mol
no of moles = mass / molar mass
no of moles of Al₂O₃ = 2000 000 g/ 101.96 g/mol
no of moles of Al₂O₃ = 19615.4 mol
From the reaction:
4Al + 3O₂ ⇒ Al₂O₃
To determine the moles of O₂ in Al₂O₃:
Then;
19615.4 mol * 3/2 mol of O₂ = 29423.1
The mass of oxygen now = 29423.1 × 32 g
= 941539.2 g
To kg;
= (941539.2 / 1000) kg
= 941.5 kg
