Answer:
2
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
let the third side ( hypotenuse ) be x , then
x² = 1² + ([tex]\sqrt{3}[/tex] )² = 1 + 3 = 4 ( take square root of both sides )
x = [tex]\sqrt{4}[/tex] = 2
