Solution :
Given : Volume = 5 L, temperature = 330 K
a). Moles in one litre,
[tex]$n_1 =\frac{n}{V}$[/tex]
[tex]$=\frac{1}{20}$[/tex]
Number of atoms = [tex]$n_1 \times N$[/tex]
= [tex]3 \times 10^{22}[/tex]
b). The thermal energy of the gas is :
[tex]$U=\frac{f}{2} nRT$[/tex]
U = 10.16 L-atm
c). Given temperature, T = 380 K
Therefore, Δ S = [tex]\frac{f}{2}nR \ln\left(\frac{T_2}{T_1}\right)[/tex]
= 0.004 L-atm/K
d). When the expansion is negligible, the pressure of the heated gas is
[tex]$P_2=\frac{nRT_2}{V}$[/tex]
= 1.56 atm