contestada

H(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ ​ 8+6x x+4 10 ​ 4x−3 ​ , , , ​ x<−7 −7≤x<−5 x≥−5 ​

Respuesta :

MrRoyal

Answer:

[tex]h(-6) = -\frac{1}{5}[/tex]

Step-by-step explanation:

Given

[tex]h(x) =\left[\begin{array}{cc}8 + 6x\ \ &x < -7\\\frac{x + 4}{10} &-7 \le x <-5 \\4x - 3\ &x \ge -5\end{array}\right[/tex]

Required

Determine h(-6)

To do this, we make use of:

[tex]h(x) = \frac{x + 4}{10}[/tex]

Because [tex]-7 \le -6 <-5[/tex]

So, we have:

[tex]h(x) = \frac{x + 4}{10}[/tex]

[tex]h(-6) = \frac{-6 + 4}{10}[/tex]

[tex]h(-6) = \frac{-2}{10}[/tex]

Simplify

[tex]h(-6) = -\frac{1}{5}[/tex]