Answer:
B = 0.159 T
Explanation:
Given that,
Current, I = 0.38 A
The average velocity of the electron, [tex]v=5.5\times 10^{-6}\ m/s[/tex]
The average magnetic force on the electron, [tex]F=1.4\times 10^{-25}\ N[/tex]
We need to find the flux density B of the magnetic field. We know that the magnetic force is given by :
[tex]F=qvB\\\\B=\dfrac{F}{qv}[/tex]
Put all the values,
[tex]B=\dfrac{1.4\times 10^{-25}}{1.6\times 10^{-19}\times 5.5\times 10^{-6}}\\\\B=0.159\ T[/tex]
So, the required flux density of the magnetic field is 0.159 T.
