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A rectangle with positive are has length represented by the expression 3x^2+5x-8 and width by 2x^2 +6x write an expression in terms of c for the perimeter and area of the rectangle give your answer in standard polynomial form and show your work

Respuesta :

Answer:

[tex]c=10x^2+22x-16\\A=6x^4+28x^3+14x^2-48x[/tex]

Step-by-step explanation:

Given

Length is [tex]l=3x^2+5x-8[/tex]

Width is [tex]w=2x^2+6x[/tex]

Perimeter of the rectangle is the sum of the sides

[tex]\Rightarrow c=2(3x^2+5x-8+2x^2+6x)\\\Rightarrow c=2(5x^2+11x-8)\\\Rightarrow c=10x^2+22x-16[/tex]

Area is given by

[tex]\Rightarrow A=(3x^2+5x-8)(2x^2+6x)\\\Rightarrow A=6x^4+18x^3+10x^3+30x^2-16x^2-48x\\\Rightarrow A=6x^4+28x^3+14x^2-48x[/tex]

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