Answer:
A
Step-by-step explanation:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]x = \frac{-2 \pm \sqrt{2^2 - 4 (-8)}}{2}[/tex]
[tex]x = \frac{-2 \pm \sqrt{4 + 32}}{2}[/tex]
[tex]x = \frac{-2 \pm \sqrt{36}}{2}[/tex]
[tex]x = \frac{-2 \pm 6}{2}[/tex]
[tex]\left \{ {{x = \frac{-2 + 6}{2}} \atop {x = \frac{-2 - 6}{2}}} \right.[/tex]
[tex]\left \{ {{x = \frac{4}{2}} \atop {x = -\frac{8}{2}}} \right.[/tex]
[tex]\left \{ {{x = 2} \atop {x = -4}} \right.[/tex]
