Answer:
[tex]d.\ 0.33 + 0.64 – (0.90)(0.33) = 0.673[/tex]
Step-by-step explanation:
Given
[tex]P(Baseball) = 33\%[/tex]
[tex]P(Baseball\ n\ Football) = 90\%[/tex]
[tex]P(Football) = 64\%[/tex]
Required
[tex]P(Baseball\ or\ Football)[/tex]
This is calculated as:
[tex]P(Baseball\ or\ Football) =P(Baseball) + P(Football) -P(Baseball\ n\ Football)[/tex]
[tex]P(Baseball\ or\ Football) = 0.33 + 0.64 - (0.90)(0.33)[/tex]
[tex]P(Baseball\ or\ Football) = 0.33 + 0.64 - 0.297[/tex]
[tex]P(Baseball\ or\ Football) = 0.673[/tex]