What is the pressure, in atm, of 24.5 L of ideal gas at 247.8 K if there are 1.8 moles present?

Answer:
p = 1.5 atm
Explanation:
pV = nRT
p = nRT/V = [1.8 mol×(0.082 atm L/mol K)×247.8 K]/24.5 L
p = 1.5 atm
Answer:
[tex]\sf\longmapsto \: pressure = 1.5 \: atm[/tex]
Explanation:
PV = NRT
We know,
Pressure=
[tex] \sf \frac{nrt}{v} [/tex]
[tex]\sf\longmapsto \: 1.8 \: moles \times (0.082 \: atm \: \frac{l}{mol} \: k \times 247.8k )\ \: ÷24.5 L[/tex]
[tex]\sf\longmapsto \: pressure = 1.5 \: atm[/tex]