Respuesta :

Answer:

[tex]height = \frac{24}{2} = 12 \: cm \\ adjacent = \frac{32}{2} = 16 \: cm[/tex]

We get a triangle of height 12 cm and adjacent 16 cm

[tex]side = \sqrt{ {12}^{2} + {16}^{2} } \\ = \sqrt{400} \\ = 20 \: cm[/tex]

DhunganaShreya

Answer:

side=√(24/2)²+(32/2)²

=√12²+16²

=√400

= 20

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