Answer:
B = 6.57 T
Explanation:
The amplitude of emf of an AC generator coil can be given by the following formula:
[tex]EMF = N\omega AB[/tex]
where,
EMF = amplitude of emf = 20 V
N = No. of turns = 50
ω = angular speed= (350 rev/min)(2π rad/1 rev)(1 min/60 s) = 36.65 rad/s
A = Cros-sectional area of coil = πr² = π(0.023 m)² = 1.66 x 10⁻³ m²
Therefore,
[tex]20\ V = (50)(36.65\ rad/s)(1.66\ x\ 10^{-3}\ m^2)B\\\\B = \frac{20\ V}{(50)(36.65\ rad/s)(1.66\ x\ 10^{-3}\ m^2)}[/tex]
B = 6.57 T
