Daniel drew a toy from a treasure chest containing 30 different toys. He selected a bouncy ball without replacement and then selected a key chain. What is the probability this could occur

Respuesta :

Answer:

[tex]Pr = \frac{1}{870}[/tex]

Step-by-step explanation:

Given

[tex]n =30[/tex]

Required

Probability of selecting 2 toys of different types

From the question, we understand that all toys are different i.e. 1 of each type.

And the selection is without replacement;

So, after the first toy is selected; there are n - 1 toys left.

So, the probability is:

[tex]Pr = \frac{1}{n} * \frac{1}{n - 1}[/tex]

Substitute [tex]n =30[/tex]

[tex]Pr = \frac{1}{30} * \frac{1}{30- 1}[/tex]

[tex]Pr = \frac{1}{30} * \frac{1}{29}[/tex]

[tex]Pr = \frac{1}{30*29}[/tex]

[tex]Pr = \frac{1}{870}[/tex]