Can someone help with this

Answer:
Step-by-step explanation:
The standard form of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex] where h and k are the coordinates of the center of the circle, and r is the radius squared. Our center is located at (-6, -4) and from the center to the outer edge is 2 units, so the radius is 2-squaraed, which is 4. That makes the equation for this circle
[tex](x-(-6))^2+(y-(-4))^2=4[/tex] which simplifies to
[tex](x+6)^2+(y+4)^2=4[/tex]