Answer:
V = 57.39 L
Explanation:
Given that,
Temperature, T = 300 K
Pressure, P = 0.987 atm
No. of moles of Ne, n = 2.30 mol
We need to find the volume of Ne. We know that, the ideal gas law is as follows :
PV = nRT
Where
P is pressure and R is gas constant
[tex]V=\dfrac{nRT}{P}\\\\V=\dfrac{2.3\times 0.0821\times 300}{0.987 }\\\\V=57.39\ L[/tex]
So, the volume of the Ne is 57.39 L.
