Answer: hello your question is incomplete attached below is the complete question
answer : Ac = 5° , A[tex]_{f}[/tex] = 2.5°
Explanation:
Bandgap energy for material A = 0.90 eV
Bandgap energy for material B = 1.10 eV
Calculate the ratio of ni for Material B to Material B
Total derivation ( d ) = d1 + d2
d = A[tex]_{c}[/tex] ( μ[tex]_{c}[/tex] - 1 ) + A[tex]_{f}[/tex] ( μ[tex]_{f}[/tex] - 1 ) ---- ( 1 )
where : d = 1° , μ[tex]_{c}[/tex] = 1.5 , μ[tex]_{f}[/tex] = 1.6
Input values into equation 1 above
1° = 0.5Ac + 0.6Af ---- ( 2 )
also d = d1 [ 1 - w/ w1 ] ------ ( 3 )
∴ d = Ac ( μ[tex]_{c}[/tex] - 1 ) ( 1 - w/w1 )
1° = Ac ( 1.5 - 1 ) ( 1 - 0.06/0.1 ) --- ( 4 )
resolving equation ( 4 )
Ac = 5°
resolving equation ( 2 )
A[tex]_{f}[/tex] = 2.5°
