Respuesta :
Answer:
1.2 × 10²⁴ atoms C
General Formulas and Concepts:
Chemistry
Atomic Structure
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Explanation:
Step 1: Define
Identify variables
[Given] 24 g C
[Solve] atoms C
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of C: 12.01 g/mol
Step 3: Convert
- [DA] Set up: [tex]\displaystyle 24 \ g \ C(\frac{1 \ mol \ C}{12.01 \ g \ C})(\frac{6.022 \cdot 10^{23} \ atoms \ C}{1 \ mol \ C})[/tex]
- [DA] Divide\Multiply [Cancel out units]: [tex]\displaystyle 1.2034 \cdot 10^{24} \ atoms \ C[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
1.2034 × 10²⁴ atoms C ≈ 1.2 × 10²⁴ atoms C