Answer:
[tex]g=6x+18[/tex]
Step-by-step explanation:
From the question we are told that:
Function
[tex]f(x)=x^3+9x^2−81x+14[/tex]
Generally 1st derivative f'(x) of Fuction f(x) is
[tex]f'(x)=3x^2+2*9(x)-81[/tex]
[tex]f'(x)=3x^2+18(x)-81[/tex]
Generally 2nd derivative f''(x) of Fuction f(x) is
Where
[tex]f''(x)=g[/tex]
Therefore
[tex]g=3x^2+18(x)-81[/tex]
[tex]g=2*3x^1+18[/tex]
[tex]g=6x+18[/tex]
