Answer:
[tex]P(81)=56.16[/tex]
Step-by-step explanation:
From the question we are told that:
Mean [tex]\mu=50[/tex]
Standard Deviation [tex]\sigma=7[/tex]
Percentile 81st
Generally Probability of 81st Percentile
[tex]P(Z<x)=81\%[/tex]
Using Standard normal Table
[tex]P(Z<0.88)=81\%[/tex]
Therefore the 81st percentile is given as
[tex]P(81)=z*\sigma *\mu[/tex]
[tex]P(81)=0.88*7*50[/tex]
[tex]P(81)=56.16[/tex]
