The estimated probability that it will take at least four patients to find one who is not an elderly patient is 0.1504.
The number of patients = 10
Elderly patients = 60%
Non-elderly patients = 100% - 60% = 40%
The probability that the first four patients are elderly will be:
= [0.6^0 × (0.4)^10] + [0.6 × (-0.6)^9] + [0.6² × (1 - 0.6)^8] + [0.6³ × (1 - 0.6)^7
= 0.000105 + 0.0016 + 0.01062 + 0.0425
= 0.1504
The probability that exactly two of three randomly selected morning appointments are with elderly patients will be:
= 0.6² × (1 - 0.6)¹.
= 0.432
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