The height of the triangle is 4 inches less than four times its
base. The area of the triangle is 112 in2. What is the height of
the triangle?

Respuesta :

Answer:

Let base = b

Given height, h is 4inches less than base. So h = b - 4

[tex]Area = \frac{1}{2} \times base \times height\\\\112 = \frac{1}{2} b \times(b-4)\\224 = b(b -4)\\b^2 - 4b -224 = 0\\\\b= \frac{4 \pm \sqrt{16 - (4\times -224)} }{2} \\\\\\b= \frac{4 + \sqrt{16 +896 } }{2} , b= \frac{4 - \sqrt{16 +896} }{2} \\\\\\b = 17.099 , -13.099[/tex]

Since length can't be negative, we take b = 17.099inches

Height ,h = b - 4 = 13.099 inches ≈ 13.1 inches