Answer:
0.122 = 12.2% probability that the student will have scored greater than 600 points on the quantitative section of the SATs.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean score of 501 points, and a standard deviation of 85 points.
This means that [tex]\mu = 501, \sigma = 85[/tex]
What is the probability that the student will have scored greater than 600 points on the quantitative section of the SATs?
This is 1 subtracted by the p-value of Z when X = 600. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{600 - 501}{85}[/tex]
[tex]Z = 1.165[/tex]
[tex]Z = 1.165[/tex] has a p-value of 0.878.
1 - 0.878 = 0.122
0.122 = 12.2% probability that the student will have scored greater than 600 points on the quantitative section of the SATs.