To find the zeros, set y = 0
[tex]-5(x-4)^2 +10 = 0[/tex]
Now try to isolate the (x-4)^2 term (move 10 to right side, divide by -5)
[tex](x-4)^2 = \frac{-10}{-5} = 2[/tex]
Next take square root of both sides (this cancels the square on (x-4))
[tex]x-4 = \pm \sqrt{2} [/tex]
[tex]x = 4 \pm \sqrt{2} [/tex]
For interpretation, x = price, y = profit
We are solving for price where profit = 0.
