A 200 milliliter sample of gas has a pressure of 1 atmosphere. If the volume of the gas is decreased to 50 milliliters at constant temperature, the new pressure of the gas will be

1) 4 atm
2) 1 atm
3) 3 atm
4) 2 atm

A 200 milliliter sample of gas has a pressure of 1 atmosphere If the volume of the gas is decreased to 50 milliliters at constant temperature the new pressure o class=

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Answer:

Answer is - 2. ...........

At constant temperature, if the volume of the sample of gas decreases, the pressure increases to 4.0atm.

Hence, option1)4 atm is the correct answer.

What is Boyle's law?

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question question;

  • Initial volume of the gas V₁ = 200mL = 0.2L
  • Initial pressure of the gas P₁ = 1.0atm
  • Final volume of the gas V₂ = 50.mL = 0.05L
  • Final pressure of the gas P₂ = ?

We substitute our given values into the expression above to determine the new pressure.

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.0atm × 0.2L ) / 0.05L

P₂ = 0.2Latm / 0.05L

P₂ = 4atm

At constant temperature, if the volume of the sample of gas decreases, the pressure increases to 4.0atm.

Hence, option1)4 atm is the correct answer.

Learn more about Boyle's law here: brainly.com/question/1437490

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