Answer:
the magnitude of the second charge is 0.000156 C.
Explanation:
Given;
mangitude of the first charge, q₁ = 0.0005 C
attractive force between the two charges, F = 7.0 N
distance between the two charges, r = 10 m
let the magnitude of the second charge = q₂
The magnitude of the second charge is calculated by applying Coulomb's law;
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
Where;
K is Coulomb's constant = 9 x 10⁹ Nm²/C²
[tex]q_2 = \frac{Fr^2}{kq_1} \\\\q_2 = \frac{7 \times \ 10^2}{(9\times 10^9)(0.0005)} \\\\q_2 = 0.000156 \ C[/tex]
Therefore, the magnitude of the second charge is 0.000156 C.
