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find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b

Respuesta :

Answer:

Step-by-step explanation:

∵A= l×b

⇒A= 4ab^2 × 6a^2b

⇒A= 24a^2b+1×b^2

Explanation: When multiplying indices, add the exponents of similar bases (that is, a^2×a = a^2+a^1 =a³) thus a^2b+1.

I hope this helped.

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