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In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles. Two of the special angles, A and B, are corresponding angles.

For the set of parallel lines intersected by a transversal, A=4x and B=-5(x-18).

Part A: Write an equation to represent the corresponding relationship betweenA andB.
Part B: Use the equation to find the measures of A and B.

Respuesta :

debmc7

Answer:

Part A: 4x = -5(x-18)

Part B: A and B both = 40 degrees

Step-by-step explanation:

Ok, corresponding angles are in the same position on the two parallel lines cut by the transversal. And they are equal in measure. So, upper right = upper right.

So A = B

4x = -5(x -18)

4x = -5x + 90

9x = 90

x = 10

Angle A = 4x = 40 degrees, which means angle B is also 40, but let's show the work:

Angle B = -5(x - 18) = -50 + 90 = 40

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