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29-04-2021
Chemistry

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pH de un jugo de naranja con [H+]=5.6×10-4M.

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Аноним Аноним

29-04-2021

Explanation:

[tex]pH = - log[H {}^{ + } ] \\ = - log(5.6 \times {10}^{ - 4} ) \\ = 3.25[/tex]

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