Answer:
True
Step-by-step explanation:
J(9 , 0) ; K(-3 , -4)
Midpoint = [tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex]
[tex]= (\frac{9+(-3)}{2},\frac{0+(-4)}{2}\\\\\\= (\frac{6}{2},\frac{-4}{2})\\\\=(3 , -2)[/tex]
(3 , -2) lies in quadrant IV
