Answer:
26.9L of SO2
Explanation:
The reaction between Sulphur and oxygen is as follows:
[tex]S_2 + 2O_2 \to 2SO_2[/tex]
This implies that:
2 moles of oxygen reacts with 1 mole of sulphur to produce 2 moles of SO₂
2 moles of oxygen also yields 2 moles of SO₂
The number of moles of oxygen given is determined as:
[tex]= 26.9 \ L \ of \ O _2 \times (\dfrac{1 \ mol \ of O_2 }{22.4 \ L}) \\\\ = 1.20 \ mol \ of \ O_2[/tex]
The number of moles of SO₂ by using the ratio is:
[tex]= 1.20 \ mol \ of \ O_2 \times (\dfrac{1 \ mol \ of \ SO_2 }{1 \ mol \ O_2}) \\ \\ = 1.20 \ mol \ of SO_2[/tex]
Finally, the volume by applying the new moles is computed as:
[tex]= 1.20 \ moles \ of \ O_2 \times ( \dfrac{1 \ mo \ of \ SO_2}{1 \ mol \ of O_2}) \times ( \dfrac{22.4 }{1 \ mol }) \\ \\ = 26.9 \ L \ of \ SO_2[/tex]
