Respuesta :

maacastrobr

Answer:

0.4 M

Explanation:

The process that takes place in an aqueous K₂HPO₄ solution is:

  • K₂HPO₄ → 2K⁺ + HPO₄⁻²

First we calculate how many K₂HPO₄ moles are there in 200 mL of a 0.2 M solution:

  • 200 mL * 0.2 M = 40 mmol K₂HPO₄

Then we convert K₂HPO₄ moles into K⁺ moles, using the stoichiometric coefficients of the reaction above:

  • 40 mmol K₂HPO₄ * [tex]\frac{2mmolK^+}{1mmolK_2HPO_4}[/tex] = 80 mmol K⁺

Finally we divide the number of K⁺ moles by the volume, to calculate the molarity:

  • 80 mmol K⁺ / 200 mL = 0.4 M

Otras preguntas